a) BL/AL =BC/AC =6/9 =2/3 (теорема о биссектрисе) => BL/BA =2/5
б) BC =√(AC*CD) => 6=√(9*CD) => CD=4
AC/CD =9/4 => AD/CD =5/4
AD/DC *CK/KL *LB/BA =1 (теорема Менелая)
5/4 *CK/KL *2/5 =1 => CK/KL =2/1
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Answers & Comments
a) BL/AL =BC/AC =6/9 =2/3 (теорема о биссектрисе) => BL/BA =2/5
б) BC =√(AC*CD) => 6=√(9*CD) => CD=4
AC/CD =9/4 => AD/CD =5/4
AD/DC *CK/KL *LB/BA =1 (теорема Менелая)
5/4 *CK/KL *2/5 =1 => CK/KL =2/1