Verified answer

Ответ: .................................................................................................................

Verified answer

√f(x) < g(x) ⇔

f(x) ≥ 0

g(x) > 0

f(x) < g(x)²

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√(4 - 3x) < x + 2

4 - 3x ≥ 0

x + 2 > 0

4 - 3x < (x + 2)²

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x ≤ 4/3

x > -2

4 - 3x < x² + 4x + 4

x² + 7x > 0

x(x + 7) > 0

++++++++++(-7) --------------- (0) ++++++++++

x ∈ (-∞, -7) U (0, +∞) пересекаем с x ≤ 4/3    x > -2

ответ x ∈ (0, 4/3]