Ответ:
Объяснение:
АВ=(2-1; 3-3 ;-1-0) = (1;0;-1) АС (0;-1;-1) ВС (-1;-1;0)
|AB| =
|AC| =
|BC| =
P (ABC) = 3* = 3
cos ∠A =
cos ∠A = =
Аналогично далее
cos ∠В =
cos ∠С =
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Answers & Comments
Ответ:
Объяснение:
АВ=(2-1; 3-3 ;-1-0) = (1;0;-1) АС (0;-1;-1) ВС (-1;-1;0)
|AB| =
|AC| =
|BC| =
P (ABC) = 3*
= 3
cos ∠A =
cos ∠A =
= 
Аналогично далее
cos ∠В =
cos ∠С =