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Lili6666
@Lili6666
November 2021
2
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Даю много баллов!!!Помогите срочно))) математика 10-11 класс
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Answers & Comments
sukonnikoffma
Y'=((e^x-4)/(x*sinx))'=((e^x-4)' *(x*sinx)-(x*sinx)' * (e^x-4))/(x*sinx)²=
=(e^x*(x*sinx)-(e^x-4)*(x' *sinx+x*(sinx)'))/(x*sinx)²=
=(
e^x*x*sinx-(e^x-4)*(sinx+x*cosx))/(x*sinx)²
2 votes
Thanks 2
kirichekov
Verified answer
(u/v)'=(u'v-uv')/v^2
((e^x-4)/(x*sinx))'=((e^x-4)'(x*sinx)-(e^x-4)(x*sinx)')/(xsinx)^2=
=(e^x(x*sinx)-(e^x-4)(sinx+x*cosx))/(xsinx)^2
3 votes
Thanks 2
sukonnikoffma
вместо второго e^x будет (e^x-4)
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Answers & Comments
=(e^x*(x*sinx)-(e^x-4)*(x' *sinx+x*(sinx)'))/(x*sinx)²=
=(e^x*x*sinx-(e^x-4)*(sinx+x*cosx))/(x*sinx)²
Verified answer
(u/v)'=(u'v-uv')/v^2((e^x-4)/(x*sinx))'=((e^x-4)'(x*sinx)-(e^x-4)(x*sinx)')/(xsinx)^2=
=(e^x(x*sinx)-(e^x-4)(sinx+x*cosx))/(xsinx)^2