Ответ:
Al4C3 + 12H2O = 4Al(OH)3 + 3CH4
14.4/144 = x/67.2
x = 6.72 л
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Ответ:
Al4C3 + 12H2O = 4Al(OH)3 + 3CH4
14.4/144 = x/67.2
x = 6.72 л