[tex]\left \{ {{4x+y = 0} \atop {4x-y=-1}} \right. \\\left \{ {{4x+y = 0} \atop {4x=-1+y}} \right. \\-1+y+y=0\\y=\frac{1}{2} \\4x=-1+\frac{1}{2} \\x=-\frac{1}{8} \\(x, y)=(-\frac{1}{8}, \frac{1}{2} )[/tex]Ответ: 1
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[tex]\left \{ {{4x+y = 0} \atop {4x-y=-1}} \right. \\\left \{ {{4x+y = 0} \atop {4x=-1+y}} \right. \\-1+y+y=0\\y=\frac{1}{2} \\4x=-1+\frac{1}{2} \\x=-\frac{1}{8} \\(x, y)=(-\frac{1}{8}, \frac{1}{2} )[/tex]
Ответ: 1