Відповідь:-42

[tex]\frac{74,7*\frac{2}{21}+(-105,3)*2\frac{3}{7}-(-105,3)*\frac{2}{21} -2\frac{3}{7}*74,7}{10} =\\=\frac{74,7*\frac{2}{21}-105,3 *\frac{17}{7}+105,3*\frac{2}{21} -\frac{17}{7}*74,7}{10} =\\=\frac{\frac{2}{21} *(74,7+105,3)-\frac{17}{7} (105,3+74,7)}{10} =\\=\frac{\frac{2}{21} *180-\frac{17}{7} *180}{10} =\frac{180(\frac{2}{21}-\frac{17}{7} )}{10} =\\=\frac{180*\frac{2-51}{21} }{10} =\frac{180*\frac{-49}{21} }{10} =\frac{-420}{10} =-42[/tex]