ADB+135°=BOC
ADB+BOC=180°
Пусть ADB--x, BOC--y
x+135=y
x+y=180
x+x+135=180
2x=45
x=22′5°=ADB
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ADB+135°=BOC
ADB+BOC=180°
Пусть ADB--x, BOC--y
x+135=y
x+y=180
x+x+135=180
2x=45
x=22′5°=ADB