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raziksergej
@raziksergej
August 2022
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для функции f(x)=12x-x^3 найдите точку максимума
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Gviona
Verified answer
F(x)=12x-x^3
f'=12-3x^2
12-3x^2=0
3(4-x^2)=0
(2-x)(2+x)=0
x=-2; x=2
_____-______-2_______+______2______-____
min. max.
f(2)=12*2-2^3=24-8=16
Y max.= 16
Координаты этой точки (2;16)
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Answers & Comments
Verified answer
F(x)=12x-x^3f'=12-3x^2
12-3x^2=0
3(4-x^2)=0
(2-x)(2+x)=0
x=-2; x=2
_____-______-2_______+______2______-____
min. max.
f(2)=12*2-2^3=24-8=16
Y max.= 16
Координаты этой точки (2;16)