y = 2 · x + 3 ←→ f(2) = 2 · 2 + 3 = 4 + 3 = 7 ; f(0) = 2 · 0 + 3 = 0 + 3 = 3 ; f(-4) = 2 · (-4) + 3 = - 8 + 3 = - 5 .
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y = 2 · x + 3 ←→ f(2) = 2 · 2 + 3 = 4 + 3 = 7 ; f(0) = 2 · 0 + 3 = 0 + 3 = 3 ; f(-4) = 2 · (-4) + 3 = - 8 + 3 = - 5 .