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robertmiralamli
@robertmiralamli
August 2022
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Для указанной функции найдите y(0), y(1), y(3)
5x^2+x-6
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aksenovarkady
У(0)=5×0^2+0-6=-6
у(1)=5×1^2+1-6=0
у(3)=5×3^2+3-6=42
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Answers & Comments
у(1)=5×1^2+1-6=0
у(3)=5×3^2+3-6=42