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taha555
@taha555
July 2022
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определить молекулярную формулу неивестного углеводорода , плотность (н.у.) равна 1,786 г/ дм3 ,а массовая доля углерода 90 %.
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IrVB
Находим молекулярную массу углеводорода
Mr = p*Vm = 1,786*22,4=40
W%=Ar*n*100%/Mr
n(C) = W%*Mr/Ar*100% = 90*40/12*100 = 3
W%(H) = 100%-90%=10%
n(H) = 10*40/1*100=4
Формула углеводорода С3Н4
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Answers & Comments
Mr = p*Vm = 1,786*22,4=40
W%=Ar*n*100%/Mr
n(C) = W%*Mr/Ar*100% = 90*40/12*100 = 3
W%(H) = 100%-90%=10%
n(H) = 10*40/1*100=4
Формула углеводорода С3Н4