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romanyuk03
@romanyuk03
July 2022
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До розчину масою 500 грам(w)NaOH=5%,додали 250 грам води.Визначте масову частку отриманого розчину.
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mrvladimir2
Verified answer
M(NaOH) = 500 г*0,05 = 25 г
m'(p.NaOH) = 500 г+250 г = 750 г
ω'(NaOH) = 25 г/750 г = 0,033 або 3,3%
Відповідь: 3,3%
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Answers & Comments
Verified answer
M(NaOH) = 500 г*0,05 = 25 гm'(p.NaOH) = 500 г+250 г = 750 г
ω'(NaOH) = 25 г/750 г = 0,033 або 3,3%
Відповідь: 3,3%