Добрый вечер решите не равенство. Created by GoodByee. algebra-ru

-----+------[0]---------_--------[60]------+-------/////////////// //////////////////Ответ: ∞ ∪ ∞ Новые вопросы в Алгебра2)4x-1=7x+83)2(3x+2)-3(x-1)=134)4(5x-1)-2(3-2x)=10Допоможіть, буду вдячна!!з поясненням, будь ласкадопоможіть будь ласкапожалуйста, помогите, просто умоляю, всю голову сломалаПомогите с интеграломПомогите с интегралом пожалуйстаЗнайдіть розв’язок нерівності: 3х − 6 < 3.Довести нерівність 3x/(9x²+1)≤1/28. Знайдіть всі значення х, при яких має зміст вираз:1/(x + 1)1. Розв'язати нерівність розв'язками нерівності. 1/(2(x + 1) - 1/2x <= 1 У вiдповiдь записати суму всіх цілих чисел, які не2. Розв'язати нерівніс…ть розв'язками нерівності. 1/x² - 3x + 2 <= 1/2 У відповідь записати добуток усіх цілих чисел, які не3. Розв'язати нерівність розв'язок. x - 8/x² - 5x + 4 > 2/x + 1. У відповідь записати найменший додатний цілиПредыдущийСледующийВместе мы знаем большеЭтот сайт использует cookies Политика Cookies . 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Добрый вечер решите не равенство...

GoodByee @GoodByee

July 2022 1 29 Report

Добрый вечер решите не равенство

Answers & Comments

Sophie155 $x-7+ \frac{(x-6)^2}{3} \geq \frac{(x+4)^2}{2} - \frac{(x+2)(x+6)}{4}$
$\frac{3(x-7)+(x-6)^2}{3} \geq \frac{2(x+4)^2}{4} - \frac{(x+2)(x+6)}{4}$
$\frac{3x-21+x^2-12x+36}{3} \geq \frac{2(x^2+8x+16)}{4} - \frac{ x^{2} +2x+6x+12}{4}$
$\frac{x^2-9x+15}{3} \geq \frac{2x^2+16x+32-x^2-8x-12}{4}$
$\frac{x^2-9x+15}{3} \geq \frac{x^2+8x+20}{4}$
$4(x^2-9x+15) \geq {3(x^2+8x+20)$
$4x^2-36x+60 \geq {3x^2+24x+60$
$4x^2-36x+60 -{3x^2-24x-60 \geq 0$
$x^2-60x \geq 0$
$x(x-60) \geq 0$
$x=0$ $x=60$

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Ответ: $(-$ ∞ $;0]$ ∪ $[60;+$ ∞ $)$