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AkiLivingston1
@AkiLivingston1
March 2022
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Доказать тождество:
1) (a+b)^2 (a-b)-2ab(b-a)-6ab(a-b)=(a-b)^3
2) (a^2+b^2)(a^4-a(во 2 степени)b^2+b^4)+(a^3-b^3)(a^3+b^3)=2a^6
3) (a^2+b^2)(c^2+d^2)=(ac+bd)^2+(ad-bc)^2
4) (a^2+cb^2)(d^2+ce^2)=(ad+cbe)^2+c(ae-bd)^2
помогите добрые люди
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