(cosα/(1-sinα))-(cosα/(1+sinα)=(cosα+cosα*sinα-cosα+cosα*sinα)/(1-sin²α)=
2cosα*sinα/cos²α=2tgα Доказано.
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(cosα/(1-sinα))-(cosα/(1+sinα)=(cosα+cosα*sinα-cosα+cosα*sinα)/(1-sin²α)=
2cosα*sinα/cos²α=2tgα Доказано.