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ERRORNOTFOUND
@ERRORNOTFOUND
July 2022
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Докажите что
(a-x)(a+x)-b(b+2x)-(a-b-x)(a+b+x)=0
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cvbdjsvjs
A^2-x^2-b^2-2xb-(a^2+ab+ax-ab-b^2-bx-ax-bx-x^2)=0
a^2-x^2-b^2-2xb-a^2-ab-ax+ab+b^2+bx+ax+bx+x^2=0
здесь все сократится
получится 0=0
0 votes
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Answers & Comments
a^2-x^2-b^2-2xb-a^2-ab-ax+ab+b^2+bx+ax+bx+x^2=0
здесь все сократится
получится 0=0