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mariamayboroda
@mariamayboroda
July 2022
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Докажите, что если а^2+b^2+c^2=0, то а(bc-a)+b(ac-b)+c(ab-c)=3abc
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mariislamova0
(a+b)(a+b+2c)=(a+b)(a+b+c)+ac+bc;
а²+аb+2ac+ba+b²+2bc=a²+ab+ac+ba+b²+bc+ac+bc
а²+2аb+2ac+b²+2bc=a²+2ab+2ac+b²+2bc
a^3+b^3+c^3-3abc=(a+b+c)(a^2+b^2+c^2-ab-bc-ac)
a^3+b^3+c^3-3abc=a³+ab²+ac²-a²b-abc-a²c+ba²+b³+bc²-ab²-b²c-abc+a²c+b²c+c³-abc-bc²-ac²
a^3+b^3+c^3-3abc=a³+b³+c³-3abc
Представьте в виде многочлена:
(y-1)(y^4+y^3+y^2+y+1)=y^5+y^4+y^3+y^2+y-y^4-y^3-y^2-y-1=y^5-1
(n+1)(n^4-n^3+n^2-n+1)=n^5-n^4+n^3-n^2+n+n^4-n^3+n^2-n+1=n^5
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Answers & Comments
а²+аb+2ac+ba+b²+2bc=a²+ab+ac+ba+b²+bc+ac+bc
а²+2аb+2ac+b²+2bc=a²+2ab+2ac+b²+2bc
a^3+b^3+c^3-3abc=(a+b+c)(a^2+b^2+c^2-ab-bc-ac)
a^3+b^3+c^3-3abc=a³+ab²+ac²-a²b-abc-a²c+ba²+b³+bc²-ab²-b²c-abc+a²c+b²c+c³-abc-bc²-ac²
a^3+b^3+c^3-3abc=a³+b³+c³-3abc
Представьте в виде многочлена:
(y-1)(y^4+y^3+y^2+y+1)=y^5+y^4+y^3+y^2+y-y^4-y^3-y^2-y-1=y^5-1
(n+1)(n^4-n^3+n^2-n+1)=n^5-n^4+n^3-n^2+n+n^4-n^3+n^2-n+1=n^5