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stoneddeer6
@stoneddeer6
July 2022
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докажите, что функция нечетная: X^3+X^5-6
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m11m
F(х)=x³+x⁵-6
F(-x)=(-x)³+(-x)⁵-6=-x³-x⁵-6=-(x³+x⁵+6)
F(x)≠-F(-x) - функция ни какая.
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Answers & Comments
F(-x)=(-x)³+(-x)⁵-6=-x³-x⁵-6=-(x³+x⁵+6)
F(x)≠-F(-x) - функция ни какая.