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ldinega
@ldinega
July 2022
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Докажите неравенство: а) (х + 7)^2>х (х +14); б)в^2+ 5 ≥ 10(в – 2).
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pomoshnik09
найдем разность выражений
a)(х+7)²-х(х+14)=( x²+14x+49)-x²-14x=x²+14x+49-x²-14x=49>0 неравенство верно
в) b²+5-10(b-2)=b²+5-10b+20=b²-10b+25=(b-5)²≥0 -неравенство верно
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Answers & Comments
a)(х+7)²-х(х+14)=( x²+14x+49)-x²-14x=x²+14x+49-x²-14x=49>0 неравенство верно
в) b²+5-10(b-2)=b²+5-10b+20=b²-10b+25=(b-5)²≥0 -неравенство верно