ac+bx+ax+bc /ay+2bx+2ax+by =x+c/2x+y
(ac+ax)+(bx+bc)/(ay+2ax)+(2bx+by)=x+c/2x+y
a(c+x)+b(x+c)/a(y+2x)+b(2x+y)=x+c/2x+y
(c+x)(a+b) /(y+2x)(a+b)=x+c/2x+y
c+x/2x+y =x+c/2x+y
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ac+bx+ax+bc /ay+2bx+2ax+by =x+c/2x+y
(ac+ax)+(bx+bc)/(ay+2ax)+(2bx+by)=x+c/2x+y
a(c+x)+b(x+c)/a(y+2x)+b(2x+y)=x+c/2x+y
(c+x)(a+b) /(y+2x)(a+b)=x+c/2x+y
c+x/2x+y =x+c/2x+y