Докажите тождество:
1) (4-x^2)^2 = (4-x^2)(4+x^2)+2x^2(x^2-4)
2) (4a+1)^2(4a-1)^2 = (16a^2+1)^2-64a^2
1) (4-x^2)^2 = (4-x^2)(4+x^2)+2x^2(x^2-4)
2) (4a+1)^2(4a-1)^2 = (16a^2+1)^2-64a^2
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Answers & Comments
Ответ:
Пошаговое объяснение:
1)(4-X²)²=((4-X²)(4+X²)+2x²(x²-4)
16-8x²+x^4=16-x^4+2x^4-8x²
16-8x²+x^4=16-8x²+x^4
2)(4a+1)²(4a-1)²=(16a²+1)²-64a²
(4a+1)²(4a-1)² =(16a²+1)²-64a²
(4a+1)²(4a-1)²= (16a²+1-8a)(16a²+1+8a)
(4a+1)²(4a-1)²=(4a-1)²(4a+1)²