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andreenkonaste
@andreenkonaste
July 2022
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Докажите тождество 2(х+у)(x-y)+(x+y)^2+(x-y)^2=4x^2
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leonardomingol
Verified answer
Раскроем скобки.
2(х+у)(x-y) + (x+y)^2 + (x-y)^2 = 2x^2 - 2y^2 + x^2 + 2xy + y^2 + x^2 - 2xy + y^2 =
2x^2 + 2x^2 = 4x^2
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Answers & Comments
Verified answer
Раскроем скобки.2(х+у)(x-y) + (x+y)^2 + (x-y)^2 = 2x^2 - 2y^2 + x^2 + 2xy + y^2 + x^2 - 2xy + y^2 = 2x^2 + 2x^2 = 4x^2