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СуперСаша2004
@СуперСаша2004
July 2022
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докажите тождество
(а+в)²+(а-в)²=2(а²+в²)
Решите уравнение
(2у²+1)²-4у²=5
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sangers
(a+b)²+(a-b)²=a²+2ab+b²+a²-2ab+b²=2a²+2b²=2*(a²+b²).
(2y²+1)²-4y²=5
4y⁴+4y²+1-4y²=5
4y⁴=4 |÷4
y⁴=1
y⁴-1=0
(y²-1)*(y²+1)=0
(y-1)*(y+1)*(y²+1)=0
y-1=0 y₁=1
y+1=0 y₂=-1.
Ответ: y₁=1 y₂=-1.
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Answers & Comments
(2y²+1)²-4y²=5
4y⁴+4y²+1-4y²=5
4y⁴=4 |÷4
y⁴=1
y⁴-1=0
(y²-1)*(y²+1)=0
(y-1)*(y+1)*(y²+1)=0
y-1=0 y₁=1
y+1=0 y₂=-1.
Ответ: y₁=1 y₂=-1.