Докажите тождество:1).(a^2+4)^2-16a^2=(a+2)^2(a-2)^22).(4a+1)^2(4a-1)^2=(16a^2+1)^2-64a^2. Created by vasiluk2000. matematika-ru

Докажите тождество:1).(a^2+4)^2-16a^2=(a+2)^2(a-2)^22).(4a+1)^2(4a-1)^2=(16a^2+1...

vasiluk2000 @vasiluk2000

July 2022 1 5 Report

Докажите тождество:
1).(a^2+4)^2-16a^2=(a+2)^2(a-2)^2
2).(4a+1)^2(4a-1)^2=(16a^2+1)^2-64a^2

Answers & Comments

enoilsantas 1) (a^2 + 4)^2 - 16a^2 = (a + 2)^2 * (a - 2)^2
a^4 + 8a^2 + 16 - 16a^2 = (a^2 + 4a + 4) * (a^2 - 4a + 4)
a^ - 8a^2 + 16 = a^4 - 4a^3 + 4a^2 + 4a^3 - 16a^2 + 16a + 4a^2-16a - 16
a^4 - 8a^2 + 16 = a^ - 8a^2 + 16
a^ - 8a^2 + 16 -a^4 + 8a^2 - 16 = 0

(4a + 1)^2 * (4a - 1)^2 = (16a^2 + 1)^2 - 64a^2
(16a^2 + 8a +1) * (16a^2 - 8a + 1) = 256a^4 + 32a^2 1 - 64a^2
256a^4 - 128a^3 + 16a^2 + 128a^3 - 64a^2 + 8a + 16a^2 -8a + 1 = 256a^4 - 32a^2 + 1
256a^4 - 32a^2 + 1 = 256a^4 - 32a^2 + 1
256a^4 - 32a^2 + 1 -256a^4 + 32a^2 - 1 = 0

8 votes Thanks 7

Answers & Comments

razlozhite na mnozhiteli1x3 xy2 6y26x228x4y xy43a3 2a218 9a4a

ploshad parallelogramma sv m2 mozhno vycheslit po formuule sabsinagdea i

2d1d2gde d1d2 diagonali romba v metrahpolzuyas etoj formuloj najdite diagona

kakogo domena pervogo urovnya ne sushestvuetadebby

reshite uravnenie3h12 9x1x 10

uprostite vyrazhenie3x1x 1 3x 13x1

razlozhite na mnozhiteli2u2 182h2 12x183y 273x212x12

uprostite vyrazhenie2a2b2 2ab2

organy vydeleniya zemnovodnyh etoa pochkib malpigievy sosudyv kozhag pochki6244cb2eed8c585eb1fedfcfafcc3182 4334

dn vysota treugolnika mnk md dk dokazhite chto treugolniki mnd i knd ravn

рекомендуемые вопросы

Helpful Links

Helpful Social