Ответ:
1) сos 110° ≈ - 0.3420
2) sin 116° ≈ 0.8988
3) tg 138° ≈ -0.9004
4) cos 120° 30' = cos 132.5° ≈ -0.6756
5) sin 125°18' = sin 125.3° ≈ 0.8161
6) tg 120°6' = tg 120.1° ≈ -1.7251
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Answers & Comments
Ответ:
1) сos 110° ≈ - 0.3420
2) sin 116° ≈ 0.8988
3) tg 138° ≈ -0.9004
4) cos 120° 30' = cos 132.5° ≈ -0.6756
5) sin 125°18' = sin 125.3° ≈ 0.8161
6) tg 120°6' = tg 120.1° ≈ -1.7251