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iravlasyuk200
@iravlasyuk200
February 2022
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sedinalana
Verified answer
1
16^(2x-1)=64
(4²)^(2x-1)=4³
2(2x-1)=3
4x-2=3
4x=5
x=1,25
2
(3/2)^(x+4)=(3/2)^3x-1
x+4=3x-1
3x-x=4+1
2x=5
x=2,5
3
(1/7)^(4x)>(1/7)^-1
4x<-1 основание меньше 1,знак меняется
x<-0,25
4
(1/3)^(x²-4x+3)≥(1/3)^(x-1)
x²-4x+3≤x-1
x²-5x+4≤0
x1+x2=5 U x1*x2=4
x1=1 U x2=4
x∈[1;4]
5
4*2^2x+7*2^x-2=0
2^x=a
4a²+7a-2=0
D=49+32=81
a1=(-7-9)/8=-2⇒2^x=-2 нет решения
a2=(-7+9)/8=1/4⇒2^x=1/4⇒x=-2
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Answers & Comments
Verified answer
116^(2x-1)=64
(4²)^(2x-1)=4³
2(2x-1)=3
4x-2=3
4x=5
x=1,25
2
(3/2)^(x+4)=(3/2)^3x-1
x+4=3x-1
3x-x=4+1
2x=5
x=2,5
3
(1/7)^(4x)>(1/7)^-1
4x<-1 основание меньше 1,знак меняется
x<-0,25
4
(1/3)^(x²-4x+3)≥(1/3)^(x-1)
x²-4x+3≤x-1
x²-5x+4≤0
x1+x2=5 U x1*x2=4
x1=1 U x2=4
x∈[1;4]
5
4*2^2x+7*2^x-2=0
2^x=a
4a²+7a-2=0
D=49+32=81
a1=(-7-9)/8=-2⇒2^x=-2 нет решения
a2=(-7+9)/8=1/4⇒2^x=1/4⇒x=-2