x² + x + 1 = 0| · (x - 1); (x - 1)(x² + x + 1) = 0; x³ - 1 = 0; x³ = 1.
x³³³³ = (x³)¹¹¹¹ = 1¹¹¹¹ = 1; x³³³= (x³)¹¹¹ = 1¹¹¹ = 1; x³³= (x³)¹¹ = 1¹¹ = 1.
х² + х = -1
Маємо: (x³³³³ + x³³³ + x³³ + x³ + 1996)/(100·(х² + х)) = (1 + 1 + 1 + 1 + 1996)/(100·(-1)) = 2000/(-100) = -20
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x² + x + 1 = 0| · (x - 1); (x - 1)(x² + x + 1) = 0; x³ - 1 = 0; x³ = 1.
x³³³³ = (x³)¹¹¹¹ = 1¹¹¹¹ = 1; x³³³= (x³)¹¹¹ = 1¹¹¹ = 1; x³³= (x³)¹¹ = 1¹¹ = 1.
х² + х = -1
Маємо: (x³³³³ + x³³³ + x³³ + x³ + 1996)/(100·(х² + х)) = (1 + 1 + 1 + 1 + 1996)/(100·(-1)) = 2000/(-100) = -20