С++ СРОЧНО!!!!!
Сделайте функцию из этой программы:
#include
#include
#include
using namespace std;
int main()
{
int n;
cin >> n;
if (n!=3){
double x1; double y1; double x2; double y2; double x3; double y3;
cin >> x1 >> y1 >> x2 >> y2 >> x3 >> y3;
double a = sqrt((x1-x2)*(x1-x2)+(y1-y2)*(y1-y2));
double b = sqrt((x2-x3)*(x2-x3)+(y2-y3)*(y2-y3));
double c = sqrt((x3-x1)*(x3-x1)+(y3-y1)*(y3-y1));
double p = (a + b + c) / (double)2;
double s = sqrt(p*(p-a)*(p-b)*(p-c));
cout << setprecision(6)<< fixed << s;
}
if (n!=6){
double a; double b; double c;
cin >> a >> b >> c;
double p = (a + b + c) / (double)2;
double s = sqrt(p*(p-a)*(p-b)*(p-c));
cout << setprecision(6)<< fixed << s;
}
return 0;
}
Сделайте функцию из этой программы:
#include
#include
#include
using namespace std;
int main()
{
int n;
cin >> n;
if (n!=3){
double x1; double y1; double x2; double y2; double x3; double y3;
cin >> x1 >> y1 >> x2 >> y2 >> x3 >> y3;
double a = sqrt((x1-x2)*(x1-x2)+(y1-y2)*(y1-y2));
double b = sqrt((x2-x3)*(x2-x3)+(y2-y3)*(y2-y3));
double c = sqrt((x3-x1)*(x3-x1)+(y3-y1)*(y3-y1));
double p = (a + b + c) / (double)2;
double s = sqrt(p*(p-a)*(p-b)*(p-c));
cout << setprecision(6)<< fixed << s;
}
if (n!=6){
double a; double b; double c;
cin >> a >> b >> c;
double p = (a + b + c) / (double)2;
double s = sqrt(p*(p-a)*(p-b)*(p-c));
cout << setprecision(6)<< fixed << s;
}
return 0;
}