a² + a ≤ 10a² - 5a + 1
a² + a - 10a² + 5a - 1 ≤ 0
- 9a² + 6a - 1 ≤ 0
9a² - 6a + 1 ≥ 0
(3a - 1)² ≥ 0
Ответ : a ∈ R
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a² + a ≤ 10a² - 5a + 1
a² + a - 10a² + 5a - 1 ≤ 0
- 9a² + 6a - 1 ≤ 0
9a² - 6a + 1 ≥ 0
(3a - 1)² ≥ 0
Ответ : a ∈ R