3(a– b) + 2(a+b – c) + b –3c = 5(a– c)
3а - 3b + 2a + 2b - 2c + b - 3c = 5a - 5c
5a - 5c = 5a - 5c
тождество доказано
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3(a– b) + 2(a+b – c) + b –3c = 5(a– c)
3а - 3b + 2a + 2b - 2c + b - 3c = 5a - 5c
5a - 5c = 5a - 5c
тождество доказано