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ivanchik693
@ivanchik693
July 2022
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50 баллов, 8 класс.
Пpeдстaвьтe в видe дрoби вырaжение:
а) 6a+5/a^2 + a-6/a
б) 5/y - 3/y+1
Найдите значение выражения:
3n - 12n^2+m / 4n
при n = 0,2; m = -2.
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ВикаВикторовна
Verified answer
А) (6а+5)/а² + (а-6)/а = (6а+5+а(а-6))/а² = (6а+5+а²-6а)/а² = (а²+5)/а²
б) 5/у - 3/(у+1) = (5(у+1)-3у)/(у(у+1)) = (5у+5-3у)/(у²+у) = (2у+5)/(у²+у)
3n - (12n²+m)/4n = (3n*4n-(12n²+m))/4n = (12n²-12n²+m)/4n = m/4n
m/4n = -2/(4*0,2) = -2/0,8 = -2,5
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Answers & Comments
Verified answer
А) (6а+5)/а² + (а-6)/а = (6а+5+а(а-6))/а² = (6а+5+а²-6а)/а² = (а²+5)/а²б) 5/у - 3/(у+1) = (5(у+1)-3у)/(у(у+1)) = (5у+5-3у)/(у²+у) = (2у+5)/(у²+у)
3n - (12n²+m)/4n = (3n*4n-(12n²+m))/4n = (12n²-12n²+m)/4n = m/4n
m/4n = -2/(4*0,2) = -2/0,8 = -2,5