Друзья, прошу, помогите. Болела и пропустила темы. Учитель как всегда не захотел...

rrrrrrrrr2015 @rrrrrrrrr2015

August 2021 1 6 Report

Друзья, прошу, помогите.
Болела и пропустила темы. Учитель как всегда не захотела помогать. А сама я не понимаю. Прошу помочь. ♥
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arsenlevadniy

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$\left \{ {{2x^2-y^2=4, \ |(\times3)} \atop {x^2+3y^2-5x=6;}} \ \right. \left \{ {{6x^2-3y^2=12,} \atop {x^2+3y^2-5x=6;}} \right. (+) \ \left \{ {{y^2=2x^2-4,} \atop {7x^2-5x=18;}} \right. \\ 7x^2-5x-18=0, \\ D=(-5)^2-4\cdot7\cdot(-18)=529=23^2, \\ x_{1,2}=\frac{5\pm23}{2\cdot7},$
$\left \{ {{ \left [ {{x=- \frac{9}{7},} \atop {x=2,}} \right. } \atop {y^2=2x^2-4,}} \right. \left [ {{ \left \{ {{x=- \frac{9}{7},} \atop {y^2=-\frac{34}{49}, \ |\ \textless \ 0}} \right. } \atop {\left \{ {{x=2,} \atop {y^2=4;}} \right. }} \right. \left [ {{ \left \{ {{x=- \frac{9}{7},} \atop {y\in\varnothing}} \right. } \atop {\left \{ {{x=2,} \atop { \left [ {{y=-2,} \atop {y=2;}} \right. }} \right. }} \right. \\ (2;-2), (2;2).$

$\left \{ {{x+y^2=2,\ |\times(-2)} \atop {2y^2+x^2=3,}} \right. \left \{ {{-2x-2y^2=-4,} \atop {2y^2+x^2=3,}} \right. (+) \ \left \{ {{-2x+x^2=-1,} \atop {y^2=2-x,}} \right. \\ x^2-2x+1=0, \\ (x-1)^2=0, \\ x-1=0, \\ x=1, \\ \left \{ {{x=1,} \atop {y^2=1,}} \right. \left \{ {{x=1,} \atop {\left [ {{y=-1,} \atop {y=1.}} \right. }} \right. \\ (1;-1), (1;1).$

rrrrrrrrr2015 Спасибо большое. Сильно благодарю!

pomogite pooooooozhalujsta 1 reshit sistemu uravnenij metodom podstanovki 2

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pomogite pooooooozhalujsta 1 reshit sistemu uravnenij metodom podstanovki 2

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