Два трактора вспахивают 400 кв. м за 4 часа. Какую площадь вспашут 10 трактоов за 5 часов.. Created by Sunnymoon123. matematika-ru

Примем за 1 площадь всего полях - вспахивает первый за 1 час у - вспахивает второй за 1 час10 * (х + у) - площадь всего поля5 * (х + у) + 9у - площадь всего поляПолучим систему{10*(x+ y) = 1{5 * (x + y) + 9y = 1 Laila9876Laila98761) 400:4=100²м - за один час2)100*10=1000 тракторы за один час вспашут3) 1000*5=5000²мОтвет: 10 тракторов за 5 часов в пашут площадь 5000м²Новые вопросы в Математикане могу решить уравнения по правилу 1)"Чтобы найти вычитаемое, нужно из уменьшаемого вычесть разность" 2x - y +4 = 0 при x = 4 если сходить из этого т…оy + 4 = 2x - 0y = 2x - 4y = 4Конечно можно решить по правилу переноса или представить все в виде суммы, но хотелось бы решить по правилу 1 ведь при изменении решений ответ не должен менятьсяС решением пожалуйстапервое окно стоит 1400 а второе на 20% больше. сколько стоит второе окно?400300987654 разьбить на класы50 БАЛОВ + розписати Розв’язати систему рівнянь:(х-2y+3z=5(x+3y-4z=-2(3x+2y-2z=4Назвіть властивості степеня з цілим показником50 балов срочно ОБЯЗАТЕЛНО!!!!! РОСПИСАТЬВідомі два векториa ( 4;- 3; 1)іb (8;-6;n) .При якому n вектори колінеарні ?50 балов срочноВідомі два векториa ( 4;- 3; 1)іb (8;-6;n) .При якому n вектори колінеарні ?Гіпотенуза прямокутного трикутника 5 см, в один з катетів 4 см. Знайти другий катет.Якщо3(2x-5)-4(x-2)=1ПредыдущийСледующийВместе мы знаем большеЭтот сайт использует cookies Политика Cookies . 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Два трактора вспахивают 400 кв. м за 4 часа. Какую площадь вспашут 10 трактоов з...

Sunnymoon123 @Sunnymoon123

July 2022 1 5 Report

Два трактора вспахивают 400 кв. м за 4 часа. Какую площадь вспашут 10 трактоов за 5 часов.

Answers & Comments

kirilldubov200p2e1t3 Примем за 1 площадь всего поля
х - вспахивает первый за 1 час
у - вспахивает второй за 1 час
10 * (х + у) - площадь всего поля
5 * (х + у) + 9у - площадь всего поля
Получим систему
{10*(x+ y) = 1
{5 * (x + y) + 9y = 1