[tex]\frac{6a+7b}{3a-4b}=\frac{6*2,4+7*0,8}{3*2,4-4*0,8}=\frac{14,4+5,6}{7,2-3,2}=\frac{20}{4} =5[/tex]
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[tex]\frac{6a+7b}{3a-4b}=\frac{6*2,4+7*0,8}{3*2,4-4*0,8}=\frac{14,4+5,6}{7,2-3,2}=\frac{20}{4} =5[/tex]