Ответ:
ctg(B)=1/tg(B)
tg(B)*1/tg(B)-cos²(B)
1-cos²(B)=sin²(B)
[tex]sin^2\beta[/tex]
Объяснение:
[tex]\displaystyle tg\beta*ctg\beta-cos^2\beta=\frac{sin\beta}{cos\beta} *\frac{cos\beta}{sin\beta} -cos^2\beta=1-cos^2\beta=sin^2\beta+cos^2\beta-cos^2\beta=sin^2\beta[/tex]
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справочные материалы:
[tex]\displaystyle \square~~~ sin^2\alpha+cos^2\alpha=1;\\ \square~~~ tg\alpha=\frac{sin\alpha}{cos\alpha} ;\\\square~~~ctg\alpha=\frac{cos\alpha}{sin\alpha}[/tex]
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Answers & Comments
Ответ:
ctg(B)=1/tg(B)
tg(B)*1/tg(B)-cos²(B)
1-cos²(B)=sin²(B)
Ответ:
[tex]sin^2\beta[/tex]
Объяснение:
[tex]\displaystyle tg\beta*ctg\beta-cos^2\beta=\frac{sin\beta}{cos\beta} *\frac{cos\beta}{sin\beta} -cos^2\beta=1-cos^2\beta=sin^2\beta+cos^2\beta-cos^2\beta=sin^2\beta[/tex]
___________________
справочные материалы:
[tex]\displaystyle \square~~~ sin^2\alpha+cos^2\alpha=1;\\ \square~~~ tg\alpha=\frac{sin\alpha}{cos\alpha} ;\\\square~~~ctg\alpha=\frac{cos\alpha}{sin\alpha}[/tex]