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enkurhak
@enkurhak
August 2022
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Рассчитайте объем водорода (н.у) который выделится при взаимодействии цинка с 0,5 молярным раствором 250 мл соляной кислоты/
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mrvladimir2
Verified answer
M(HCl) = 0.25 л*0,5*36,5 г/моль =4,5625 г
4.5625 г х л
Zn + 2HCl = ZnCl2 + H2
71 г 22,4 л
х= 1,439 л
22 votes
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Answers & Comments
Verified answer
M(HCl) = 0.25 л*0,5*36,5 г/моль =4,5625 г4.5625 г х л
Zn + 2HCl = ZnCl2 + H2
71 г 22,4 л
х= 1,439 л