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l24011998
@l24011998
July 2022
1
5
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ЭДС источника тока 10В. Когда источник замкнут на резистор, сила тока в цепи 5А. Найдите работу стороне сил за 30 с работы источника
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saassl
А=q U = I t U = 5A*10B*30c=1500 Дж
q=It
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А=q U = I t U = 5A*10B*30c=1500 Дж
q=It