Ответ:

дано

m(CxHy) = 2.8 g

V(C) = 4.48 L

m(H2O) = 3.6 g

D(CH4) = 4.375

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CxHy - ?

n(C) = n(CO2) = V(CO2) / Vm = 4.48 / 22.4= 0.2 mol

n(H) = 2n(H2O) = 2*m(H2O) / M(H2O) = 2*3.6 / 18 = 0.4 mol

M(CxHy) = D(CxHy) *14 = 4.375 * 14 =70 g/mol

n(C) : n(H) = 0.2 : 0.4 = 2;4

C2H4

M(C2H4) = 28 g/mol

n = M(CxHy)  / M(C2H4) = 70 / 28 = 2.5 раз

n(C) : n(H)  = 0.2*2.5 : 0.4*2.5 = 5 : 10

C5H10

M(C5H10) = 70 g/mol

ответ C5H10

Объяснение: