Ответ:
-5,4
Объяснение:
=[tex]\frac{2m}{(1-m)(1+m)}[/tex] - [tex]\frac{1+m}{1-m}[/tex] - [tex]\frac{m}{1+m}[/tex] = [tex]\frac{2m-(1+m)(1+m)-m(1-m)}{(1-m)(1+m)}[/tex] = [tex]\frac{2m-1-2m-m^{2}-2+m^{2} }{(1-m)(1+m)}[/tex] = [tex]\frac{-3}{1-m^{2} }[/tex]
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Ответ:
-5,4
Объяснение:
=[tex]\frac{2m}{(1-m)(1+m)}[/tex] - [tex]\frac{1+m}{1-m}[/tex] - [tex]\frac{m}{1+m}[/tex] = [tex]\frac{2m-(1+m)(1+m)-m(1-m)}{(1-m)(1+m)}[/tex] = [tex]\frac{2m-1-2m-m^{2}-2+m^{2} }{(1-m)(1+m)}[/tex] = [tex]\frac{-3}{1-m^{2} }[/tex]