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Pomoshnik13
@Pomoshnik13
July 2022
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Эксцентриситет эллипса 5х^2+9y^2=45 равен...
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IrkaShevko
Verified answer
5x² + 9y² = 45
x²/3² + y²/(√5)² = 1
a = 3 - большая полуось
b = √5 - малая полуось
c² = a² - b² = 9 - 5 = 4; c = 2 -
2c = 4 - расстояние между фокусами
e - эксцентриситет
e = c/a = 2/3
Ответ: 2/3
1 votes
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Answers & Comments
Verified answer
5x² + 9y² = 45x²/3² + y²/(√5)² = 1
a = 3 - большая полуось
b = √5 - малая полуось
c² = a² - b² = 9 - 5 = 4; c = 2 -
2c = 4 - расстояние между фокусами
e - эксцентриситет
e = c/a = 2/3
Ответ: 2/3