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Margo310
@Margo310
December 2021
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Электровоз ,развивая мощность 820 квт,проходит путь 2,4 км за 2 мин .Чему равна в этом случае сила тяги
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ТатМих
Verified answer
N=FS/t
N=820 квт=820 000 Вт
S=2.4 км=2400 м
t=2мин=120 с
F=Nt/S
F
=820000*120/2400=820000/20=41000 Н=
41 кН
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Verified answer
N=FS/tN=820 квт=820 000 Вт
S=2.4 км=2400 м
t=2мин=120 с
F=Nt/S
F=820000*120/2400=820000/20=41000 Н=41 кН