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@375298
July 2022
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энергия фотона электромагнитной волны E= 4,8 * 10 ^ 19 Дж. определите длину волны и ее частоту
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sokolovvovikn
Verified answer
E=h*v
v=E/h=4,8*10^-19/6,63*10^-34=7,2*10^14 Гц
L=c/v=3*10^8/7,2*10^14=4,16*10^-7 м=416 нм
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Verified answer
E=h*vv=E/h=4,8*10^-19/6,63*10^-34=7,2*10^14 Гц
L=c/v=3*10^8/7,2*10^14=4,16*10^-7 м=416 нм