October 2021 0 6 Report
Если 18 г смеси, состоящей из меди и железа, может взаимодействовать с 8415 л хлора, то каков состав исходной смеси в % ответ: m(Fe)=8.46 m(Cu)=9.54 пожааалуйста помогите.
Please enter comments
Please enter your name.
Please enter the correct email address.
You must agree before submitting.
More Questions From This User See All
perepishite rasstavlyaya znaki prepinaniya 1 ne uspel ya otojtina neskolko sazhe
Answer
dokazat tozhdestva trigonometriya sin60 acos30a ctg80 atg10a a alf
Answer
15 ballov7 8 klassy materialy dlya 7 8 klassov pozhalujsta pomogiteee nado resh
Answer
complete the sentence so youve finally realized what a mistake youre making
Answer
?...
Answer

Helpful Links

Helpful Social

Copyright © 2024 SCHOLAR.TIPS - All rights reserved.