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DinaTae04
@DinaTae04
July 2022
2
42
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если корни уровнения
2х²-5х-8=0 будут Х₁ и Х₂
найдите сумму Х₁Х₂²+Х₁²Х₂.
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alexsmm
По теореме Виета x1+x2=2.5 x1*x2=-4.
x1x2^2+x1^2x2=x1x2(x1+x2)= -10
1 votes
Thanks 2
dim10102806
2x^2-5x-8=0 |:2
x^2-2,5x-4=0
По теореме Виета
x1+x2=2,5,
x1*x2=-4;
x1*x2^2+x1^2*x2=x1*x2(x1+x2)=-2,5*4=-10
Ответ: {-10}
2 votes
Thanks 3
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Answers & Comments
x1x2^2+x1^2x2=x1x2(x1+x2)= -10
x^2-2,5x-4=0
По теореме Виета
x1+x2=2,5,
x1*x2=-4;
x1*x2^2+x1^2*x2=x1*x2(x1+x2)=-2,5*4=-10
Ответ: {-10}