Ответ:2
Mr(CaSO4)=40+32+64=136
W%(CaSO4)=100-20.9=79.1
Mr(CaSO4*nH2O)=Mr(CaSO4)*100/79.1=136*100/79.1=172
n(H2O)={Mr(CaSO4*nH2O)-Mr(CaSO4)}/18=(172-136)/18=36/18=2
Объяснение:
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Ответ:2
Mr(CaSO4)=40+32+64=136
W%(CaSO4)=100-20.9=79.1
Mr(CaSO4*nH2O)=Mr(CaSO4)*100/79.1=136*100/79.1=172
n(H2O)={Mr(CaSO4*nH2O)-Mr(CaSO4)}/18=(172-136)/18=36/18=2
Объяснение: