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zhuldyzai98
@zhuldyzai98
August 2021
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Если в геометрической прогрессии первый член равен 2,а четвертый -16,то найдите сумму первых шести членов данной прогрессии
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manyny06
B₁ = 2, b₄ = -16
b₄ = b₁* g ³
g³ = b₄ \ b₁ = -16 \ 2 = -8 ⇒ g = -2
S₆ = b₁ * ( 1-g⁶) \ ( 1-g)
S₆ = 2 ( 1 - (-2)⁶ ) \ (1- (-2) )
S₆ = 2 * (1-64) \ (1+2)
S₆ = -42
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Answers & Comments
b₄ = b₁* g ³
g³ = b₄ \ b₁ = -16 \ 2 = -8 ⇒ g = -2
S₆ = b₁ * ( 1-g⁶) \ ( 1-g)
S₆ = 2 ( 1 - (-2)⁶ ) \ (1- (-2) )
S₆ = 2 * (1-64) \ (1+2)
S₆ = -42