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ugzan
@ugzan
September 2021
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если второй и тридцатый члены арифметической прогрессии равны 3 и -109. как найти 16-ый ее член
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sedinalana
Verified answer
A2=3,a30=-109
d=(a30-a2)/(30-2)=(-109-3)/28=-112/28=-4
a1=a2-d=3-(-4)=7
a16=a1+15d=7-15*4=7-60=-53
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Verified answer
A2=3,a30=-109d=(a30-a2)/(30-2)=(-109-3)/28=-112/28=-4
a1=a2-d=3-(-4)=7
a16=a1+15d=7-15*4=7-60=-53