sinα+cosα=1/2; (sinα+cosα)²=(1/2)²;
2sinαcosα+cos²α=1+2sinαcosα=1/4;
sinαcosα=1/4-1 /2 =-3/4/2 = -3/8
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
sinα+cosα=1/2; (sinα+cosα)²=(1/2)²;
2sinαcosα+cos²α=1+2sinαcosα=1/4;
sinαcosα=1/4-1 /2 =-3/4/2 = -3/8