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79108434535
@79108434535
July 2022
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найдите значение выражения 2x^2+7x+5/x3-1 + 4x+3/ x^2+x+1 - 5 / x-1 при x =1,1 / - это черта между дробями
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vzural74
2 × 1,1^2 + 7 × 1,1 + 5=
15,12
1,1 × 3 − 1 + 4 × 1,1 + 3=
9,7
1,1^2 + 1,1 + 1 − 5
=
−1,69
1.1-1=0.1
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Answers & Comments
1,1 × 3 − 1 + 4 × 1,1 + 3= 9,7
1,1^2 + 1,1 + 1 − 5 = −1,69
1.1-1=0.1